16x^2/4x=24

Solution for 16x^2/4x=24 equation:

16x^2/4x=24

We move all terms to the left:

16x^2/4x-(24)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We multiply all the terms by the denominator


16x^2-24*4x=0

Wy multiply elements

16x^2-96x=0

a = 16; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·16·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*16}=\frac{0}{32}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*16}=\frac{192}{32}
=6
$